Draw a line segment \(AD\) perpendicular to \(BC\).
It is an altitude for this triangle.
It can be observed that the length of \(BD\) and \(DC\) is also same.
Therefore, \(AD\) is also a median of this triangle.
Give first the step you will use to separate the variable and then solve the equation:
(a) x – 1 = 0
(b) x + 1 = 0
(c) x – 1 = 5
(d) x + 6 = 2
(e) y – 4 = – 7
(f) y – 4 = 4
(g) y + 4 = 4
(h) y + 4 = – 4