\(SnCl_{2} \)
\(CCl_{4} \)
\(SO_{3} \)
\(BrF_{5}\)
Step 1: Understand VSEPR theory.
VSEPR (Valence Shell Electron Pair Repulsion) theory predicts the geometry of molecules based on the repulsion between electron pairs in the valence shell of the central atom.
The shape of a molecule depends on the number of bonding pairs and lone pairs around the central atom.
Step 2: Analyze the given species.
\(SnCl_{2}\): Central atom Sn has 2 bonding pairs and 1 lone pair. The shape is bent or V-shaped.
\(CCl_{4}:\) Central atom C has 4 bonding pairs and no lone pairs. The shape is tetrahedral.
\(SO_{3}\): Central atom S has 3 bonding pairs and no lone pairs. The shape is trigonal planar.
\(BrF_{5}\): Central atom Br has 5 bonding pairs and 1 lone pair. The shape is square pyramidal.
Step 3: Determine the correct answer.
\(BrF_{5}\) has a square pyramidal shape due to 5 bonding pairs and 1 lone pair around the central bromine atom.
Samples of four metals A, B, C, and D were added one by one to the following solutions. The results obtained were tabulated as follows:
Use the table above to answer the following questions about metals A, B, C, and D:
(i) Which is the least reactive metal?
(ii) What would be observed if C is added to a solution of copper sulphate?
(iii) Arrange the metals A, B, C, and D in the order of their decreasing reactivity.