Question:

Use the formula \(v=\sqrt\frac{γp}{ρ}\)  to explain why the speed of sound in air 

(a) is independent of pressure, 

(b) increases with temperature, 

(c) increases with humidity.

Updated On: Nov 2, 2023
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Solution and Explanation

Take the relation: 

\(v=\sqrt\frac{γp}{ρ}\)          \(........(i)\)

Where,

Density, ρ \(=\frac{Mass}{Volume}=\frac{M}{V}\)

M= Molecular weight of that gas 

v= Volume of the gas

Hence, equation (i) reduces to: 

\(v=\sqrt \frac{γPv}{M}\)     \(........(ii)\)

Now from the ideal gas equation for n = 1: 

PV = RT 

For constant T, PV = Constant 

Since both M and γ are constants, v = Constant

Hence, at a constant temperature, the speed of sound in a gaseous medium is independent of the change in the pressure of the gas.

Take the relation:

\(v=\sqrt \frac{γP}{ρ}\)    \(........(i)\)

For one mole of an ideal gas, the gas equation can be written as:

PV = RT

\(p=\frac{RT}{V}\)      \(........(ii)\)

Substituting equation (ii) in equation (i), we get:

\(v=\sqrt \frac{γRT}{Vρ}=\sqrt \frac{γRT}{M}\)    \(........(iv)\)

Where, 

Mass, M = ρV is a constant

γ and R are also constants

We conclude from equation (iv) that . \(v∝\sqrt{T}\).

Hence, the speed of sound in a gas is directly proportional to the square root of the temperature of the gaseous medium, i.e., the speed of the sound increases with an increase in the temperature of the gaseous medium and vice versa.

Let \(v_m\,and\,v_d\) be the speeds of sound in moist air and dry air respectively.

Let \(ρ_m\,and\,ρ_d\) be the densities of moist air and dry air respectively

Take the relation:

\(v=\sqrt \frac{γP}{ρ}\)

Hence, the speed of sound in moist air is:

\(v_m=\sqrt \frac{γP}{ρ_m}\)   \(........(i)\)

And the speed of sound in dry air is

\(v_d=\sqrt \frac{γP}{ρ_d}\)  \(........(ii)\)

On dividing equations (i) and (ii), we get:

\(\frac{v_d}{v_d}=\sqrt \frac{γP}{ρ_m}* \frac{P_d}{y_ρ}=\sqrt\frac{p_d}{p_m}\)

However, the presence of water vapour reduces the density of air, i.e.,

ρd<pm

∴ vm>vd

Hence, the speed of sound in moist air is greater than it is in dry air. Thus, in a gaseous medium, the speed of sound increases with humidity.

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Concepts Used:

Sound

Sound is a vibration that propagates the mechanical wave of displacement and pressure, through a medium can be of any matter. In other words, the sound is the thin line between Music sound and Noise.

Types of Sounds:

Sound can be divided into two types depending on its frequency. The following are:-

Infrasonic Waves:

  • Infrasonic waves have a frequency lower than 20 Hz. Since it is below the human hearing range, it is inaudible to humans.
  • However, several other living organisms use these waves to communicate, whales, sharks, elephants, hippopotamus, etc. these waves are also used in the scientific field, it is used to study upcoming earthquakes, volcanic eruptions, human heart rates, rock formation stages, etc.

Ultrasonic waves:

  • Ultrasonic waves have a frequency higher than 20 kHz. Since it is above the human hearing range, it is inaudible to humans.
  • These waves are used in the scientific field, it is used to study human heart rates, to take sonograms, navigation of directions, imaging things, uniform sample mixing, communication, testing of samples, etc.