Student $A: $ Average reading $= \frac{3.01+2.99}{2} = 3.0 \, g$
Student $B :$ Average reading$= \frac{3.05+2.95}{2} = 3.0 \, g$
For both the students $A$ and $B$, average reading is close to the correct reading (i.e., $3.0\, g$). Hence, both recorded accurate readings. But the readings recorded by student $A$ are more precise as they differ only by $? 0.01$, whereas readings recorded by the student $B$ are differ by $? 0.05$. Thus, the results of student $A$ are both precise and accurate.