Question

Two spheres with unequal radii have charge - if they are connected by a thin wire what will happen to charges?

Answer 1

Potential Equilibrium: When two conductors are connected by a wire, they come to the same electric potential. This is because charges move through the wire until there is no potential difference between the conductors.
Surface Charge Density: On a spherical conductor, the surface charge density (charge per unit area) is inversely proportional to the radius of the sphere. So, a smaller sphere will have a higher surface charge density compared to a larger sphere, given the same amount of charge. 
Redistribution of Charges: If two spheres with unequal radii are connected and one of them initially has a charge, charges will move from the sphere with the higher surface charge density (smaller sphere) to the one with the lower surface charge density (larger sphere) until both spheres reach the same potential. If both spheres initially have charges, then the movement of charges will depend on the magnitude and sign of the charges on both spheres and their radii. 
Final State: The exact distribution of charges at the end will depend on the initial charges and the radii of the spheres. However, the key idea is that charges will redistribute until both spheres have the same electric potential. The smaller sphere will have a higher surface charge density than the larger sphere in this final state. 
In summary, when two spheres with unequal radii are connected by a thin wire, charges will move between the spheres until they both come to the same electric potential, with the smaller sphere ending up with a higher surface charge density than the larger one.