Question:

Two satellites of earth, $ S_1 $ and $ S_2 $ , are moving in the same orbit. The mass of $ S_1 $ is four times the mass of $ S_2 $ . Which one of the following statements is true ?

Updated On: Apr 8, 2024
  • The time period of $ S_1 $ is four times that of $ S_2 $
  • The potential energies of earth and satellite in the two cases are equal
  • $ S_1 $ and $ S_2 $ are moving with the same speed
  • The kinetic energies of the two satellites are equal
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The Correct Option is C

Solution and Explanation

\(K.E. =\frac{ GMm }{2r}\) \(\Rightarrow\) Kinetic energies are unequal.
\(T =\frac{2 \pi r ^{\frac 32}}{\sqrt{ GM }}\) \(\Rightarrow\) Time period are equal.
P.E. \(=-\frac{\text {GMm}}{r}\) \(\Rightarrow\) Potential energies are unequal.
\(v =\sqrt{\frac{ GM }{ r }}\) \(\Rightarrow\) Orbital speeds are equal.

So, the cortrect option is (C): \(S_1\)​ and \(S_2\)​ are moving with the same speed.

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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].