Question

Two resistors of Ω 3 and Ω 2 are connected in series and a potential difference of 5 V is applied across them. The potential difference across Ω2 resistor is

• A. 2 V
• B. 1 V
• C. 5 V
• D. 30 V

Answer 1

The Correct Option is A

In a series circuit, the total resistance is the sum of individual resistances. The total resistance \( R_{\text{total}} \) is: \[ R_{\text{total}} = R_1 + R_2 = 3 \, \Omega + 2 \, \Omega = 5 \, \Omega \] The total current \( I \) in the circuit is given by Ohm's law: \[ I = \frac{V}{R_{\text{total}}} = \frac{5 \, \text{V}}{5 \, \Omega} = 1 \, \text{A} \] Now, to find the potential difference across the 2 \(\Omega\) resistor, we use Ohm's law again: \[ V_2 = I \times R_2 = 1 \, \text{A} \times 2 \, \Omega = 2 \, \text{V} \]

The correct option is (A): \(2 V\)