The total resistance \(R_{total}\) of the parallel combination is:
\( \frac{1}{R_{total}} = \frac{1}{2} + \frac{1}{4} = \frac{3}{4} \),
so \(R_{total} = \frac{4}{3} \Omega\). Using Ohmβs law:
\( I = \frac{V}{R_{total}} = \frac{16}{\frac{4}{3}} = 12 \text{ A} \)