Question:

Two point dipoles \( \mathbf{p_k} \) and \( \mathbf{L_k} \) are located at \( (0,0,0) \) and \( (1m, 0, 2m) \) respectively. The resultant electric field due to the two dipoles at the point \( (1m, 0, 0) \) is

Show Hint

The electric field due to a dipole decreases as the cube of the distance from the dipole.
Updated On: Jan 12, 2026
  • \( \frac{9p}{32 \pi \epsilon_0} \hat{k} \)
  • \( \frac{7p}{32 \pi \epsilon_0} \hat{k} \)
  • \( \frac{7p}{32 \pi \epsilon_0} \hat{i} \)
  • \( \frac{-7p}{32 \pi \epsilon_0} \hat{k} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Electric Field Due to Dipole.
The electric field due to a dipole at a distance \( r \) from its center is given by: \[ E = \frac{1}{4 \pi \epsilon_0} \frac{2p \cos \theta}{r^3} \] where \( p \) is the dipole moment, \( \theta \) is the angle between the line joining the observation point and the dipole axis, and \( r \) is the distance from the dipole.
Step 2: Conclusion.
The correct answer is (A), \( \frac{9p}{32 \pi \epsilon_0} \hat{k} \).
Was this answer helpful?
0
0

Top Questions on Electrostatics

View More Questions