Question:
Two point charges -q and +q are placed at a distance of L, as shown in the figure.
The magnitude of electric field intensity at a distance R (R>>L) varies as:
Two point charges -q and +q are placed at a distance of L, as shown in the figure.
The magnitude of electric field intensity at a distance R (R>>L) varies as:
The magnitude of electric field intensity at a distance R (R>>L) varies as:
Updated On: Jul 19, 2024
- \(\frac{1}{R^2}\)
- \(\frac{1}{R^3}\)
- \(\frac{1}{R^4}\)
- \(\frac{1}{R^6}\)
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The Correct Option is B
Solution and Explanation
It is electric dipole at large distance electric field density
\(E=\frac{KP}{R^3}\sqrt{1+3\cos^2\theta}\)
\(\therefore\ E \propto \frac{1}{R^3}\)
Therefore, the correct option is (B) : \(\frac{1}{R^3}\)
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Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).