Question:

Two point charges of $1 \,\mu C$ and $-1\, \mu C$ are separated by a distance of $100\, ?$. A point $P$ is at a distance of $10 \,cm$ from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at $P$ will be

Updated On: Jul 7, 2022
  • $9 \,N \,C^{-1}$
  • $0.9 \,N \,C^{-1}$
  • $90 \,N \,C^{-1}$
  • $0.09 \,N \,C^{-1}$
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The Correct Option is D

Solution and Explanation

The point lies on equatorial line of a short dipole. $\therefore E=\frac{2ql}{4\pi\varepsilon_{0}r^{3}}$ $=\frac{9\times10^{9}\times10^{-6}\times10^{-8}}{\left(10^{-1}\right)^{3}}$ $=0.09\,N\,C^{-1}$
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Concepts Used:

Electric Field

Electric Field is the electric force experienced by a unit charge. 

The electric force is calculated using the coulomb's law, whose formula is:

\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)

While substituting q2 as 1, electric field becomes:

 \(E=k\dfrac{|q_{1}|}{r^{2}}\)

SI unit of Electric Field is V/m (Volt per meter).