Question:
Two parallel large thin metal sheets have equal surface charge densities $\left(\sigma=26.4\times10^{-12} c m^{2}\right)$ of opposite signs. The electric field between these sheets is
Two parallel large thin metal sheets have equal surface charge densities $\left(\sigma=26.4\times10^{-12} c m^{2}\right)$ of opposite signs. The electric field between these sheets is
Updated On: Jul 5, 2022
- $1.5 \,N/C$
- $1.5 \times 10^{-10} N/C$
- $3\,N/C$
- $3 \times 10^{-10} N/C$
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The Correct Option is C
Solution and Explanation
Electric field between sheets is
$E=\sigma/ \varepsilon_{0} =\frac{26.4\times10^{-12}}{8.85\times10^{-12}} $
$\approx3\, N/ C$
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Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).