Question:

Two numbers A and B are less than a third number C by 15% and 32%, respectively. By what percent (%) is number B less than the number A?

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To find the percentage difference between two numbers, first find the difference, then divide by the reference number and multiply by 100.
Updated On: Feb 16, 2025
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The Correct Option is D

Solution and Explanation

Let the number \( C \) be the reference number. Then, \[ A = C \times \left( 1 - \frac{15}{100} \right) = C \times 0.85 \] and \[ B = C \times \left( 1 - \frac{32}{100} \right) = C \times 0.68 \] We are asked to find the percentage by which \( B \) is less than \( A \). The difference between \( A \) and \( B \) is: \[ A - B = C \times 0.85 - C \times 0.68 = C \times (0.85 - 0.68) = C \times 0.17 \] The percentage by which \( B \) is less than \( A \) is: \[ \frac{A - B}{A} \times 100 = \frac{C \times 0.17}{C \times 0.85} \times 100 = \frac{0.17}{0.85} \times 100 = 20% \] Thus, number \( B \) is \( \boxed{20%} \) less than number \( A \).
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