Question:
Two masses of 10 kg and 20 kg respectively are tied together by a massless spring. A force of 200 N is applied on a 20 kg mass as shown in figure. At the instant shown the acceleration of 10 kg mass is $ 12\text{ }m/{{s}^{2}}, $ the acceleration of 20 kg mass is
Two masses of 10 kg and 20 kg respectively are tied together by a massless spring. A force of 200 N is applied on a 20 kg mass as shown in figure. At the instant shown the acceleration of 10 kg mass is $ 12\text{ }m/{{s}^{2}}, $ the acceleration of 20 kg mass is
Updated On: Nov 26, 2022
- zero
- $ 10\text{ }m/{{s}^{2}} $
- $ 4\text{ }m/{{s}^{2}} $
- $ 12\text{ }m/{{s}^{2}} $
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The Correct Option is C
Solution and Explanation
Force on the block of 10 kg
$=ma=10\times 12=120N $
The total force applied = 200 N The force acting on block of 20 kg
$=200-120=80\text{ }N $
The acceleration of block of 20 kg
$=\frac{80}{20}=4\,m/{{s}^{2}} $
$=ma=10\times 12=120N $
The total force applied = 200 N The force acting on block of 20 kg
$=200-120=80\text{ }N $
The acceleration of block of 20 kg
$=\frac{80}{20}=4\,m/{{s}^{2}} $
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Concepts Used:
Newtons Laws of Motion
Newton’s First Law of Motion:
Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.
Newton’s Second Law of Motion:
Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.
Mathematically, we express the second law of motion as follows:
Newton’s Third Law of Motion:
Newton’s 3rd law states that there is an equal and opposite reaction for every action.