Two identical short bar magnets are placed mutually perpendicular, the resultant magnetic field at a point on the prolongation of the magnetic axis of P is inclined at 30\(^{\circ}\) with the axis. Compare the magnetic moments of the two magnets.
Two identical short bar magnets are placed mutually perpendicular, the resultant magnetic field at a point on the prolongation of the magnetic axis of P is inclined at 30\(^{\circ}\) with the axis. Compare the magnetic moments of the two magnets.
Solution and Explanation
Top Questions on Oscillations
- Identify which of the following wave functions describe(s) travelling wave(s).
(\(A_0, B_0, a\), and \(b\) are positive constants of appropriate dimensions)- IIT JAM PHY - 2025
- Physics
- Oscillations
- Consider the superposition of two orthogonal simple harmonic motions \(y_1 = a \cos 2\omega t\) and \(y_2 = b \cos(\omega t + \phi)\). If \(\phi = \pi\), the resultant motion will represent
(a, b and \(\omega\) are constants with appropriate dimensions)- IIT JAM PHY - 2025
- Physics
- Oscillations
- A mass of 0.5 kg is attached to a spring of force constant 200 N/m. What is the time period of oscillation?
- MHT CET - 2025
- Physics
- Oscillations
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity):
- JEE Advanced - 2025
- Physics
- Oscillations
- A spring is stretched by \( 0.2 \, \text{m} \) when a mass of \( 0.5 \, \text{kg} \) is suspended to it. The time period of the spring when \( 0.5 \, \text{kg} \) mass is replaced with a mass of \( 0.25 \, \text{kg} \) is (Acceleration due to gravity \( = 10 \, \text{m/s}^2 \))
- AP EAPCET - 2025
- Physics
- Oscillations