Question:

Two identical capacitors are joined in parallel, charged to a potential $V$ , separated and then connected in series, the positive plate of one is connected to the negative of the other. Which of the following is true?

Updated On: Jul 7, 2022
  • The charges on the free plated connected together are destroyed
  • The energy stored in the system increases
  • The potential difference between the free plates is $2 V$
  • The potential difference remains constant
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The Correct Option is C

Solution and Explanation

When the two capacitors charged to same potential are connected in series, then total potential difference $V' = V_{1}+V_{2} = V+V = 2V$
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Concepts Used:

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The total capacitance of this equivalent single capacitor depends both on the individual capacitors and how they are connected. There are two simple and common types of connections, called series and parallel, for which we can easily calculate the total capacitance.

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When one terminal of a capacitor is connected to the terminal of another capacitors , called series combination of capacitors. 

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Capacitors can be connected in two types which are in series and in parallel.  If capacitors are connected one after the other in the form of a chain then it is in series. In series, the capacitance is less.

When the capacitors are connected between two common points they are called to be connected in parallel.

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