Let the distance be \( d \) km. We know the time difference is \( \frac{1}{2} \) hour. Setting up the equation using the time formula for both cyclists, we solve for \( d \), which gives \( d = 10 \, \text{km} \).
Let the distance be \( d \) km.
% Time for the second cyclist
The time taken by the second cyclist is \( \frac{d}{5} \) hours.
% Time for the first cyclist
The time taken by the first cyclist is \( \frac{d}{4} \) hours.
We are told that the first cyclist arrives 30 minutes (or \( \frac{1}{2} \) hour) later than the second cyclist. So:
\[
\frac{d}{4} - \frac{d}{5} = \frac{1}{2}
\]
To solve for \( d \), first find a common denominator:
\[
\frac{5d - 4d}{20} = \frac{1}{2}
\]
\[
\frac{d}{20} = \frac{1}{2}
\]
\[
d = 10 \, \text{km} = 10000 \, \text{m}
\]
Final Answer: The correct answer is (c) 10000 m.