Question

Two currents 3 mA and 5 mA are flowing towards the junction in a circuit and three currents 1 mA, 1.5 mA and x are flowing away. The value of x (in mA) is

• A. 8
• B. 10.5
• C. 2.5
• D. 5.5

Answer 1

The Correct Option is D

According to Kirchhoff's Current Law (KCL), the total current entering a junction must equal the total current leaving the junction. 

Current entering the junction: $3 \text{ mA} + 5 \text{ mA} = 8 \text{ mA}$ 

Current leaving the junction: $1 \text{ mA} + 1.5 \text{ mA} + x = 2.5 \text{ mA} + x$ 

Equating the incoming and outgoing currents, we have: $8 \text{ mA} = 2.5 \text{ mA} + x$ 

Solving for $x$: $x = 8 \text{ mA} - 2.5 \text{ mA} = 5.5 \text{ mA}$ 

Therefore, the value of $x$ is 5.5 mA. 

The correct answer is (4) 5.5.