Question:

Two conducting spheres of radii $R_{1}$ and $R_{2}$ are charged with charges $Q_{1}$ and $Q_{2}$ respectively. On bringing them in contact, there is

Updated On: Jun 20, 2022
  • no change in the energy of the system
  • an increase in the energy of the system if $ Q_{1}R_{2}\ne Q_{2}R_{1}$
  • always a decrease in the energy of the system
  • a decrease in the energy of the system if $ Q_{1}R_{2}=Q_{2}R_{1} $
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The Correct Option is D

Solution and Explanation

Potential $V_{1}=\frac{1}{4 \pi \varepsilon_{0}} \frac{Q_{1}}{R_{1}}$
and $V_{2}=\frac{1}{4 \pi \varepsilon_{0}} \frac{Q_{2}}{R_{2}}$
If $V_{1}=V_{2}$
then $\frac{Q_{1}}{R_{1}}=\frac{Q_{2}}{R_{2}}$
or $Q_{1} R_{1}=Q_{2} R_{1}$
In this case, there will be no flow of charges. However, if the given spheres have unequal potentials then the charges shall flow from higher potential to lower potential. Flow of charges shall be accompanied by loss of energy.
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Concepts Used:

Electrostatic Potential

The electrostatic potential is also known as the electric field potential, electric potential, or potential drop is defined as “The amount of work that is done in order to move a unit charge from a reference point to a specific point inside the field without producing an acceleration.”

SI Unit of Electrostatic Potential:

SI unit of electrostatic potential - volt

Other units - statvolt

Symbol of electrostatic potential - V or φ

Dimensional formula - ML2T3I-1

Electric Potential Formula:

The electric potential energy of the system is given by the following formula:

U = 1/(4πεº) × [q1q2/d]

Where q1 and q2 are the two charges that are separated by the distance d.