Question:

Two coins are tossed simultaneously. The probability of getting at least one head is :

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"At least one" is the complement of "None". Probability(at least one head) = 1 - Probability(no heads). Here, $1 - 1/4 (TT) = 3/4$.
Updated On: Mar 9, 2026
  • 1/4
  • 1/2
  • 3/4
  • 1
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Probability is defined as the number of favorable outcomes divided by the total number of possible outcomes (sample space).

Step 2: Listing the Sample Space (S):
When two coins are tossed, the possible outcomes are:
$S = \{HH, HT, TH, TT\}$.
Total number of outcomes $n(S) = 4$.
Step 3: Identifying Favorable Outcomes (E):
"At least one head" means we can have one head or two heads.
Favorable outcomes: $\{HH, HT, TH\}$.
Number of favorable outcomes $n(E) = 3$.
Step 4: Final Answer:
$$P(E) = \frac{n(E)}{n(S)} = \frac{3}{4}$$
The probability is 3/4.
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