Question

Two coils have a mutual inductance of 0.55 H. The current changes in the first coil according to the equation \( I = I_0 \sin \omega t \), where \( I_0 = 10 \, A \) and \( \omega = 100 \, \text{rad/s} \). The maximum value of emf in the second coil is?

• A. \( 2\pi \)
• B. 5π
• C. 5π x 10

Hint:

The maximum induced emf depends on the rate of change of current in the first coil and the mutual inductance between the coils.

Answer 1

The Correct Option is B

The induced emf in the second coil is given by Faraday's law of induction. The maximum value of emf can be found using the formula: \[ \mathcal{E} = M \frac{dI}{dt} \] where \( M \) is the mutual inductance and \( \frac{dI}{dt} \) is the rate of change of current.