Question:

Two charges, each \( +q \), are placed at the corners of an isosceles triangle ABC of sides BC and AC, 2a. D and E are the mid-points of BC and CA. The work done in taking a charge \( Q \) from D to E is

Show Hint

In a system with symmetry, if the points of movement are equidistant from the charges, no work is required.
Updated On: Jan 6, 2026
  • \( \frac{eqQ}{8\pi \epsilon_0} \)
  • \( \frac{qQ}{4\pi \epsilon_0} \)
  • Zero
  • \( \frac{3qQ}{4\pi \epsilon_0} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Since points D and E are equidistant from the charges, the potential at these points is the same, meaning no work is done in moving the charge from D to E.

Step 2: Conclusion.
The work done is zero, corresponding to option (c).
Was this answer helpful?
0
0

Top Questions on Electrostatics

View More Questions