Question:

Two capacitors of capacitance 2 \(\mu\)F and 4 \(\mu\)F are connected in series. The equivalent capacitance is:

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Series capacitors reduce overall capacitance.
Updated On: Jan 5, 2026
  • 6 \(\mu\)F
  • 1.33 \(\mu\)F
  • 8 \(\mu\)F
  • 2 \(\mu\)F
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The Correct Option is B

Solution and Explanation

For series combination, \[ \frac{1}{C}=\frac{1}{2}+\frac{1}{4}=\frac{3}{4} \Rightarrow C=\frac{4}{3}=1.33\ \mu\text{F} \]
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