Question:

Two bulbs of 40 W and 60 W are connected to a 220 V source. The ratio of their resistances will be:

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Remember: Resistance is inversely proportional to power for same voltage: \[ R \propto \frac{1}{P}. \]
  • \(4 : 3\)
  • \(3 : 4\)
  • \(2 : 3\)
  • \(3 : 2\)
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The Correct Option is A

Solution and Explanation

Power \(P\), voltage \(V\), and resistance \(R\) are related by: \[ P = \frac{V^2}{R} \implies R = \frac{V^2}{P}. \] For the two bulbs: \[ R_1 = \frac{220^2}{40}, \quad R_2 = \frac{220^2}{60}. \] Therefore, the ratio of resistances: \[ \frac{R_1}{R_2} = \frac{220^2/40}{220^2/60} = \frac{60}{40} = \frac{3}{2}. \] But since \(R_1\) corresponds to the 40 W bulb and \(R_2\) to 60 W bulb, ratio \(R_1 : R_2 = 3 : 2\). Note: This matches option (D), so correct answer is (D) \(3 : 2\).
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