Question:

Two blocks, of mass $1\, kg$ and $2\, kg$ respectively, are connected by a spring and kept on a frictionless table. The blocks are pulled apart, so that the spring is stretched, and released from rest. At a certain instant of time, the block of mass $1 \,kg$, is found to be moving at a speed $2 \,m / s$. What must be the speed of the other block at this instant?

Updated On: Aug 1, 2022
  • 1 m/s
  • 0.5 m/s
  • 4 m/s
  • 0.25 m/s
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The Correct Option is A

Solution and Explanation

According to conservation of linear momentum $0=m_{1} v_{1}+m_{2} v_{2}$ $0=1 \times 2 \times 2 \times v^{2}$ $v_{2}=-1 m / s$ Negative sign shows that $ 2\,kg $ is pulled in a opposite direction to that of mass $ 1 \,kg $ .
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Concepts Used:

Newtons Laws of Motion

Newton’s First Law of Motion:

Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion:

Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.

Mathematically, we express the second law of motion as follows:

Newton’s Third Law of Motion:

Newton’s 3rd law states that there is an equal and opposite reaction for every action.