Question:
Two balls of equal masses are thrown upwards along the same vertical direction at an interval of 2 s, with the same initial velocity of 39.2 m/s. The two balls will collide at a height of
Two balls of equal masses are thrown upwards along the same vertical direction at an interval of 2 s, with the same initial velocity of 39.2 m/s. The two balls will collide at a height of
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In projectile motion, objects thrown with the same initial velocity will collide at a point based on their time difference and motion equations.
Updated On: Jan 6, 2026
- 39.2 m
- 73.5 m
- 78.4 m
- 117.6 m
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The Correct Option is B
Solution and Explanation
Step 1: Initial velocity and time interval.
The initial velocity for both balls is the same, and they are thrown with a 2-second time difference. Using kinematic equations, we calculate the height at which they meet based on their relative motions.
Step 2: Conclusion.
The balls collide at 73.5 m, which is the correct answer.
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