Correct answer: 1 sigma bond and \(2\pi\) bonds
Explanation:
In a nitrogen molecule (\(N_2\)), the two nitrogen atoms are connected by a triple bond. A triple bond consists of:
- 1 sigma (σ) bond: formed by the head-on overlap of orbitals
- 2 pi (π) bonds: formed by the side-by-side overlap of p orbitals
Therefore, the triple bond in \(N_2\) contains 1 sigma bond and 2 pi bonds.
| List-I Tetrahedral Complex | List-II Electronic configuration |
|---|---|
| (A) TiCl4 | (I) e2, t20 |
| (B) [FeO4]2- | (II) e4, t23 |
| (C) [FeCl4]- | (III) e0, t22 |
| (D) [CoCl4]2- | (IV) e2, t23 |