Question

Total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula $C_{4}H_{8}O$ is:

• A. 8
• B. 10
• C. 11
• D. 6

Hint:

When counting isomers, always consider both ring size and possible stereoisomers (cis/trans) due to ring strain and substituents.

Answer 1

The Correct Option is D

We are asked to count all possible isomers (structural and stereoisomers) for cyclic ethers with the molecular formula C₄H₈O. This formula corresponds to saturated cyclic ethers (with one ring and one oxygen atom, no double bonds).

Let us identify the different ring sizes and substitutions:

1. Three-membered ring ethers (Oxiranes/Epoxy compounds):
- Ethyloxirane (1-ethyl-oxirane)
- Methylmethyloxirane (2-methyl-oxirane, both cis and trans isomers) → 2 stereoisomers

2. Four-membered ring ethers (Oxetanes):
- Methyl-substituted oxetane (on different carbon positions)
- 2 stereoisomers (cis/trans) possible depending on substitution pattern

3. Tetrahydrofuran derivative (5-membered ring):
- 2-methyltetrahydrofuran → exists as cis/trans stereoisomers

So we have:
- 1 from ethyloxirane
- 2 from methylmethyloxirane (cis/trans)
- 1 from methyl-substituted oxetane
- 2 from methyltetrahydrofuran (cis/trans)

Total = 1 + 2 + 1 + 2 = 6 isomers