Question:

To maintain a rotor at a uniform angular speed of 200 rad s-1, an engine needs to transmit a torque of 180 N m. What is the power required by the engine ? (Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque). Assume that the engine is 100% efficient.

Updated On: Nov 7, 2023
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Solution and Explanation

Angular speed of the rotor, ω = 200 rad/s 
Torque required, τ = 180 Nm 
The power of the rotor (P) is related to torque and angular speed by the relation: 

P = τω 

= 180 × 200 

= 36 × 103 = 36 kW 

Hence, the power required by the engine is 36 kW.

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Concepts Used:

Torque

Torque is a moment of force. Torque is measured as a force that causeque is also defined as the turning effect of force on the axis of rotation. Torque is chs an object to rotate about an axis and is responsible for the angular acceleration. Characterized with “T”.

How is Torque Calculated?

Torque is calculated as the magnitude of the torque vector T for a torque produced by a given force F

T = F. Sin (θ)

Where,

 r - length of the moment arm,

θ - the angle between the force vector and the moment arm.

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Types of Torque

Torque is of two types:

  1. Static torque
  2. Dynamic torque