Question

Three resistors each of 4 Ω, 0.4 Ω and 0.04 Ω are connected in series combination. Their equivalent resistance is

• A. 4.8 Ω
• B. 4.44 Ω
• C. 4 Ω
• D. 0.44 Ω

Answer 1

The Correct Option is B

The equivalent resistance of three resistors connected in series is given by: $$R_{eq} = R_1 + R_2 + R_3$$ 

Given the resistances are $R_1 = 4 \, \Omega$, $R_2 = 0.4 \, \Omega$, and $R_3 = 0.04 \, \Omega$. 

Therefore, $$R_{eq} = 4 + 0.4 + 0.04 = 4.44 \, \Omega$$