Question:

Three point charges $ +q,-2q $ and $ +q $ are placed at points $ (x=0,y=a,x=0), $ $ (x=0,y=0,z=0) $ and $ (x=a,y=0,z=0), $ respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are

Updated On: Jun 23, 2023
  • $ \sqrt{2}\,qa $ along $ +y $ direction
  • $ \sqrt{2}\,qa $ along the line joining points $ (x=0,y=0,z=0) $ and $ (x=a,y=a,z=0) $
  • $ qa $ along the line joining points $ (x=0,y=0,z=0) $ and $ (x=a,y=a,z=0) $
  • $ \sqrt{2}\,qa $ along $ +x $ direction
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The Correct Option is B

Solution and Explanation

Key Idea Electric dipole moment is a vector quantity directed from negative charge to the similar positive charge. Choose the three coordinate axes as x, y and i and plot the charges with the given coordinates as shown. $ O $ is the origin at which $ -2q $ charge is placed. The system is equivalent to two dipoles along $ x $ and $ y- $ directions respectively. The dipole moments of two dipoles are shown in figure.The resultant dipole moment will be directed along $ OP $ where $ P=(a,\,\,a,\,\,0) $ . The magnitude of resultant dipole moment is $ p=\sqrt{{{p}^{2}}+{{p}^{2}}}=\sqrt{{{(qa)}^{2}}+{{(qa)}^{2}}} $ $ =\sqrt{2}qa $
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Concepts Used:

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