Question:
Three persons A, B, and C are standing in queue. There are five persons between A and B and eight persons between B and C. If there are three persons ahead of C and 21 behind A, then what could be the minimum number of persons in the queue?
Three persons A, B, and C are standing in queue. There are five persons between A and B and eight persons between B and C. If there are three persons ahead of C and 21 behind A, then what could be the minimum number of persons in the queue?
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For problems involving queues, consider the relative positions and the number of persons between others to determine the total number.
Updated On: Oct 7, 2025
- 40
- 27
- 28
- 41
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The Correct Option is C
Solution and Explanation
The given information is as follows:
- 5 persons between A and B.
- 8 persons between B and C.
- 3 persons ahead of C.
- 21 persons behind A.
The positions of A, B, and C must be arranged in the following way:
- A has 3 people ahead and 21 behind, which means A is in position 4.
- B is 5 persons away from A, so B is in position 10.
- C is 8 persons away from B, so C is in position 19.
Therefore, the total number of persons in the queue is:
\[ \text{Total} = \text{Position of C} + \text{Persons behind C} = 19 + 9 = 28 \]
Thus, the minimum number of persons in the queue is \( \boxed{28} \).
- 5 persons between A and B.
- 8 persons between B and C.
- 3 persons ahead of C.
- 21 persons behind A.
The positions of A, B, and C must be arranged in the following way:
- A has 3 people ahead and 21 behind, which means A is in position 4.
- B is 5 persons away from A, so B is in position 10.
- C is 8 persons away from B, so C is in position 19.
Therefore, the total number of persons in the queue is:
\[ \text{Total} = \text{Position of C} + \text{Persons behind C} = 19 + 9 = 28 \]
Thus, the minimum number of persons in the queue is \( \boxed{28} \).
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