Question:

Three boys and three girls are to be seated around a table in a circle. Among them the boy X does not want any girl neighbour and the girl Y does not want any boy neighbour. How many such arrangements are possible?

Updated On: Oct 1, 2024
  • 5
  • 6
  • 4
  • 2
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The Correct Option is C

Solution and Explanation

The positions of X and Y are fixed, with the three boys grouped together around X in the center, and the three girls grouped together around Y in the center.
The number of arrangements for boys=\((3 − 1)! = 2! = 2\)
Similarly for girls=\(2! = 2\)
\(\therefore\) Total number of ways= \(2\times2=4\)
The correct option is (C): 4

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