Question:
Three blocks of masses $2\, kg , 3 \,kg$ and $5 \,kg$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F=10 \,N$, then tension $T_{1}=$
Three blocks of masses $2\, kg , 3 \,kg$ and $5 \,kg$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F=10 \,N$, then tension $T_{1}=$
Updated On: Feb 27, 2024
- 1 N
- 5 N
- 8 N
- 10 N
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The Correct Option is C
Solution and Explanation
Total mass of the system, $M=m_{1}+m_{2}+m_{3} $$
=2+3+5$
$=10\, kg$
Force $F=10\, N$
Hence, acceleration, $a=\frac{F}{M}=1 \,ms ^{-2}$
Now, tension $T_{1}$ can be calculated as,
$T_{1}=\left(m_{2}+m_{3}\right) a=8 \times 1=8\, N$
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Concepts Used:
Tension
A force working along the length of a medium, especially if this force is carried by a flexible medium like cable or rope is called tension. The flexible cords which bear muscle forces to other parts of the body are called tendons.
Net force = 𝐹𝑛𝑒𝑡 = 𝑇−𝑊=0,
where,
T and W are the magnitudes of the tension and weight and their signs indicate a direction, be up-front positive here.
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