Question:
There are two identical springs each of spring constant k. Here springs, pulley and rods are massless and block has mass m. What is the extension of each spring at equilibrium ?
There are two identical springs each of spring constant k. Here springs, pulley and rods are massless and block has mass m. What is the extension of each spring at equilibrium ?
Updated On: Jan 18, 2023
- $\frac{mg}{k}$
- $\frac{2mg}{k}$
- $\frac{mg}{2k}$
- $\frac{3mg}{4k}$
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The Correct Option is A
Solution and Explanation
Draw a free body diagram of above figure
FBD of lower rod
$k x+k x =2 \,m g$
$\Rightarrow \, x =\frac{m g}{k} $
FBD of lower rod
$k x+k x =2 \,m g$
$\Rightarrow \, x =\frac{m g}{k} $
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Concepts Used:
Newtons Laws of Motion
Newton’s First Law of Motion:
Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.
Newton’s Second Law of Motion:
Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.
Mathematically, we express the second law of motion as follows:
Newton’s Third Law of Motion:
Newton’s 3rd law states that there is an equal and opposite reaction for every action.