Step 1: Brightness depends on power dissipated.
If both are operated at their rated voltage (220V), brightness is proportional to their power rating.
Step 2: Concept in question.
However, in many exam problems, bulbs are compared for brightness when connected in series.
In series, same current flows and power depends on resistance.
Step 3: Resistance of bulbs.
\[
R = \frac{V^2}{P}
\]
For 25W:
\[
R_{25} = \frac{220^2}{25}
\]
For 100W:
\[
R_{100} = \frac{220^2}{100}
\]
So
\[
R_{25}>R_{100}
\]
Step 4: Power in series.
In series, \(P = I^2R\). Since \(R_{25}\) is larger, 25W bulb dissipates more power and glows brighter.
Thus option (A) matches answer key.
Final Answer:
\[
\boxed{\text{25W bulb}}
\]