Question

There are 8 houses in a line and in each house, only one boy lives with the conditions as given below:
Jack is not the neighbour of Siman.
Harry is just next to the left of Larry.
There is at least one to the left of Larry.
Paul lives in one of the two houses in the middle.
Mike lives in between Paul and Larry.
If at least one lives to the right of Robert and Harry is not between Taud and Larry, then which one of the following statements is not correct?

• A. Robert is not at the left end.
• B. Robert is in between Simon and Taud.
• C. Taud is in between Paul and Jack.
• D. There are three persons to the right of Paul.

Hint:

In linear arrangement puzzles, always fix the definite positions first (like H–L together) before testing the flexible positions. Then check each condition against all valid cases.

Answer 1

The Correct Option is D

Step 1: Understanding the fixed positions
We know that Harry (H) is immediately to the left of Larry (L), so they must be together as \( H \, L \). Larry cannot be in position 1, because there must be at least one person to his left. Paul (P) lives in either position 4 or 5 (the two middle houses). Mike (M) lives between Paul and Larry — meaning M’s position number must be strictly between those of P and L. Step 2: Testing possible placements
Case 1: \( P = 4 \) and \( L = 7 \) (with \( H = 6 \)) → M can be at 5. Case 2: \( P = 5 \) and \( L = 8 \) (with \( H = 7 \)) → M can be at 6. Other arrangements like \( L = 3 \) with \( H = 2 \) and \( P = 5 \) also work, as long as M is between P and L. Step 3: Counting persons to the right of Paul
If \( P = 4 \) → Houses to the right = positions 5, 6, 7, 8 → 4 persons. If \( P = 5 \) → Houses to the right = positions 6, 7, 8 → 3 persons. Since both \( P = 4 \) and \( P = 5 \) are valid, the statement “There are three persons to the right of Paul” is not always true. Step 4: Conclusion
The only option that is not necessarily correct in all valid arrangements is option (d). \[ \boxed{\text{Option (d) is the correct choice.}} \]