To solve this problem, let's follow these steps:
- Determine the initial number of engineers. Since 99% of the 100 aspirants are engineers: 0.99 × 100 = 99
- Let x be the number of engineers who leave the classroom. The remaining engineers would be 99 - x.
- After x engineers leave, the total number of aspirants becomes 100 - x.
- We need the percentage of engineers to be 98%, thus setting up the equation:
\[\frac{99-x}{100-x}=0.98\]
- Solve the equation:
\[\frac{99-x}{100-x}=0.98\]
Simplify:
\[99-x=0.98(100-x)\]
Expand:
\[99-x=98-0.98x\]
Rearranging terms:
\[-x+0.98x=98-99\]
Simplify further:
\[-0.02x=-1\]
Isolating x:
\[x=\frac{-1}{-0.02}=50\]
- Hence, 50 engineers must leave the classroom to make the percentage of engineers drop to 98%.
Therefore, the correct answer is 50.