Question:
The volume of hydrogen at NTP displaced by that.amount of current which displaced 1 .08 g of Ag(equivalent weight of Ag = 108) will be
The volume of hydrogen at NTP displaced by that.amount of current which displaced 1 .08 g of Ag(equivalent weight of Ag = 108) will be
Updated On: Jul 7, 2022
- 1120 cc
- 11.2 cc
- 112 cc
- 11200 cc
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The Correct Option is C
Solution and Explanation
$g$ e of hydrogen $= g$ e of $Ag$
$\frac{W}{1} = \frac{1.08}{108} = 0.01\,g$
$2g\, H_2$ has volume at $N.T.P. = 22400 \,cc$.
$0.01\,g\, H_2$ has volume at $ N.T.P = \frac{22400}{2} \times 0.01$
$ = 112\,cc$.
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Notes on Nernst Equation
Concepts Used:
Nernst Equation
This equation relates the equilibrium cell potential (also called the Nernst potential) to its concentration gradient across a membrane. If there is a concentration gradient for the ion across the membrane, an electric potential will form, and if selective ion channels exist the ion can cross the membrane.
