At STP, 1 mole of any ideal gas occupies 22.4 liters.
- The molar mass of hydrogen gas (H2) is 2 grams per mole.
- The number of moles of hydrogen gas in 10 grams is: \[ \frac{10 \, \text{grams}}{2 \, \text{grams/mole}} = 5 \, \text{moles} \]
Now, using the molar volume at STP: \[ \text{Volume} = 5 \, \text{moles} \times 22.4 \, \text{liters/mole} = 112 \, \text{liters} \] Thus, the volume occupied by 10 grams of hydrogen gas at STP is 112 Liters.
Given: Mass of hydrogen gas = 10 g
At STP (Standard Temperature and Pressure): 1 mole of any ideal gas occupies 22.4 liters.
Molar mass of hydrogen (H2) = 2 g/mol
So, number of moles in 10 g of H2: \[ \text{Moles} = \frac{10}{2} = 5 \] Volume occupied = 5 moles × 22.4 L/mole = 112 liters
Correct answer: 112 Liters