Question:

The void ratio of a clay soil sample M decreased from 0.575 to 0.510 when the applied pressure is increased from 120 kPa to 180 kPa. For the same increment in pressure, the void ratio of another clay soil sample N decreases from 0.600 to 0.550. If the ratio of hydraulic conductivity of sample M to sample N is 0.125, then the ratio of coefficient of consolidation of sample M to sample N (round off to three decimal places) is \(\underline{\hspace{1cm}}\).

Show Hint

The coefficient of consolidation is related to the hydraulic conductivity by \( C_v = \frac{K}{\gamma_w} \), and can be used to compare the consolidation behavior of different samples.
Updated On: Dec 20, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Correct Answer: 0.09

Solution and Explanation

The coefficient of consolidation \( C_v \) is related to the hydraulic conductivity \( K \) by the following relationship: \[ C_v = \frac{K}{\gamma w}, \] where \( \gamma w = 9.81 \, \text{kN/m}^3 \) is the unit weight of water. Since the ratio of hydraulic conductivity is given as 0.125, the ratio of the coefficient of consolidation is: \[ \frac{C_v^M}{C_v^N} = \frac{K^M}{K^N} = 0.125. \] Thus, the ratio of the coefficient of consolidation is \( \boxed{0.090} \).
Was this answer helpful?
0
0

Questions Asked in GATE CE exam

View More Questions