Question

The value of van't Hoff factors for KCl, NaCl and \( K_2SO_4 \) respectively are ......

• A. 2, 2 and 2
• B. 2, 2 and 3
• C. 1, 1 and 2
• D. 1, 1 and 1

Hint:

The van't Hoff factor (\( i \)) is equal to the number of ions produced by the dissociation of one formula unit of the compound in solution.

Answer 1

The Correct Option is B

Step 1: Understand the van't Hoff factor. 
The van't Hoff factor (\( i \)) represents the number of particles a compound dissociates into in solution. 
For ionic compounds, \( i \) depends on the degree of dissociation. 
Step 2: Analyze the given compounds. 1. KCl: 
Dissociates into \( K^+ \) and \(Cl^-\). 
Total particles = 2. \( i = 2 \). 2. NaCl: 
Dissociates into \( Na^+ \) and \( Cl^-\). 
Total particles = 2. \( i = 2 \). 3. \( K_2SO_4 \): 
Dissociates into \( 2K^+ \) and \( SO_4^{2} \). 
Total particles = 3. \( i = 3 \). 
Step 3: Determine the correct answer. 
The van't Hoff factors for KCl, NaCl, and \( K_2SO_4 \) are 2, 2, and 3, respectively.