Question:

The unit vector in the direction of \(3\vec{i}-9\vec{j}\) is

Show Hint

Unit vector = vector divided by its magnitude.
  • \(\dfrac{3\vec{i}-9\vec{j}}{-6}\)
  • \(\dfrac{3\vec{i}-9\vec{j}}{6}\)
  • \(\dfrac{3\vec{i}-9\vec{j}}{\sqrt{90}}\)
  • \(\dfrac{3\vec{i}-9\vec{j}}{\sqrt{70}}\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Magnitude \(\|3\vec{i}-9\vec{j}\|=\sqrt{3^{2}+(-9)^{2}}=\sqrt{9+81}=\sqrt{90}\). Unit vector \(=\dfrac{1}{\|\cdot\|}\times\) vector \(=\dfrac{3\vec{i}-9\vec{j}}{\sqrt{90}}\) (which simplifies to \(\dfrac{\vec{i}-3\vec{j}}{\sqrt{10}}\)).
Was this answer helpful?
0
0

Top Questions on Vector Algebra

View More Questions