Radius of hydrogen atom, r = 0.5 \(\AA\) = 0.5 × \(10^{-10}\;\text m\)
Volume of hydrogen atom = \(\frac{4}{3}\pi r ^3\)
=\(\frac{4}{3}\times\frac{22}{7}\times(0.5 \times10^{-10})^3\)
= 0.524 × \(10^{-30} \text m^3\)
1 mole of hydrogen contains \(6.023\)× \(10^{23}\) hydrogen atoms.
\(\therefore\) Volume of 1 mole of hydrogen atoms =\(6.023\) × \(10^{23}\)× \(0.524\) × \(10^{-30}\)
= 3.16 × \(10^{-7}\text m^3\)
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