Let the position vector be \(\vec{r} = x\hat{i} + y\hat{j}\). Then:
x = A cos ωt
y = 2A cos ωt
This represents simple harmonic motion along both the x and y axes.
$\frac{x}{A}$ = cos ωt
$\frac{y}{2A}$ = cos ωt
Therefore: $\frac{x}{A} = \frac{y}{2A}$
y = 2x
This is the equation of a straight line, so the path is not parabolic or elliptical.
The motion is periodic and simple harmonic along the line y = 2x.
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is: