Let the position vector be \(\vec{r} = x\hat{i} + y\hat{j}\). Then:
x = A cos ωt
y = 2A cos ωt
This represents simple harmonic motion along both the x and y axes.
$\frac{x}{A}$ = cos ωt
$\frac{y}{2A}$ = cos ωt
Therefore: $\frac{x}{A} = \frac{y}{2A}$
y = 2x
This is the equation of a straight line, so the path is not parabolic or elliptical.
The motion is periodic and simple harmonic along the line y = 2x.
A particle is subjected to simple harmonic motions as: $ x_1 = \sqrt{7} \sin 5t \, \text{cm} $ $ x_2 = 2 \sqrt{7} \sin \left( 5t + \frac{\pi}{3} \right) \, \text{cm} $ where $ x $ is displacement and $ t $ is time in seconds. The maximum acceleration of the particle is $ x \times 10^{-2} \, \text{m/s}^2 $. The value of $ x $ is:
Two simple pendulums having lengths $l_{1}$ and $l_{2}$ with negligible string mass undergo angular displacements $\theta_{1}$ and $\theta_{2}$, from their mean positions, respectively. If the angular accelerations of both pendulums are same, then which expression is correct?