Question

The total number of ions produced from the compound \(\text{Cr}(\text{NH}_3)_6]\text{Cl}_3\) in aqueous solution is:

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

The Correct Option is C

To determine the total number of ions produced from the compound \([\text{Cr}(\text{NH}_3)_6]\text{Cl}_3\) in aqueous solution, we need to understand the dissociation process of the compound in water:

1. The compound is a complex salt consisting of a coordination complex \([\text{Cr}(\text{NH}_3)_6]^{3+}\) and chloride ions Cl^-.
2. In aqueous solution, the compound dissociates into its constituent ions: \[[\text{Cr}(\text{NH}_3)_6]^{3+} + 3\text{Cl}^- \]
3. Upon dissociation, one \([\text{Cr}(\text{NH}_3)_6]^{3+}\) ion and three Cl^- ions are formed.
4. Adding the ions together, the total number of ions produced is \(1 + 3 = 4\).

Thus, the total number of ions produced in the solution is 4.

Answer 2

To determine the total number of ions produced from the compound [Cr(NH₃)₆]Cl₃ in aqueous solution, we need to understand how it dissociates.

The compound [Cr(NH₃)₆]Cl₃ is a coordination compound. When dissolved in water, it dissociates into its constituent ions:

[Cr(NH₃)₆]Cl₃ (aq) → [Cr(NH₃)₆]³⁺ (aq) + 3Cl^- (aq)

From the dissociation equation, we can see that it produces:

• 1 [Cr(NH₃)₆]³⁺ cation
• 3 Cl^- anions

Therefore, the total number of ions produced is 1 + 3 = 4.