Question:
The time period of an earth satellite in circular orbit is independent of
The time period of an earth satellite in circular orbit is independent of
Updated On: Aug 15, 2022
- the mass of the satellite
- radius of its orbit
- both the mass and radius of the orbit
- neither the mass of the satellite nor the radius of its orbit.
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The Correct Option is A
Solution and Explanation
The time period of satellite is given by
$T = 2\pi\sqrt{\frac{\left(R+h\right)^{3}}{GM}}$
where, R + h = radius of orbit satellite, M = mass of earth.
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].