Question

The terminal voltage of the battery, whose emf is\(10V\) and internal resistance \(1\), when connected through an external resistance of \(42\) as shown in the figure is:

• A. \(4 V\)
• B. \(6 V\)
• C. \(8 V\)
• D. \(10 V\)

Answer 1

The Correct Option is C

The terminal voltage is given by:
$V_{terminal} = E - Ir$
where $E$ is the emf, $I$ is the current, and $r$ is the internal resistance.
- Total resistance, $R_\text{total} = 4 \, \Omega + 1 \, \Omega = 5 \, \Omega$.
- Current, $I = \frac{E}{R_total} = \frac{10}{5} = 2 \, A$.
- Terminal voltage, $V_{terminal} = 10 - 2 \times 1 = 8 \, V$.