We use the Fahrenheit-Celsius conversion formula:
\[
F = \frac{9}{5}C + 32
\]
Given that the Fahrenheit temperature is twice the Celsius temperature:
\[
F = 2C
\]
Substituting \( F = \frac{9}{5}C + 32 \):
\[
2C = \frac{9}{5}C + 32
\]
Solving for \( C \):
\[
2C - \frac{9}{5}C = 32
\]
\[
\frac{10C - 9C}{5} = 32
\]
\[
\frac{C}{5} = 32
\]
\[
C = 160^\circ C
\]
\[
F = 2C = 320^\circ F
\]