Question:
The surface area of the cylinder \(x^2+z^2 = 4\) inside the cylinder \(x^2 + y^2 = 4\) is:
The surface area of the cylinder \(x^2+z^2 = 4\) inside the cylinder \(x^2 + y^2 = 4\) is:
Updated On: Aug 12, 2024
- 4
- 8
- 16
- 32
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The Correct Option is D
Solution and Explanation
The correct option is(D):32
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